[tex]( {2}^{29} + {2}^{29} ) \div {1.024}^{2} = ..... \\ [/tex]
..............
Penjelasan dengan langkah-langkah:
Soal Dan Penyelesaian Nya :
2^29 + 2^29 ÷ 1.024^2
= 2^1 x 2^29 ÷ 1.024^2
= 2^29 + 1 ÷ 1.024^2
= 2^30 ÷ 1.024^2
= 2^30 ÷ 2^10 x 2
= 2^30 ÷ 2^20
= 2^30 - 20
= 2^10
by alwiandikaa26
semoga dapat membantu Anda
Penjelasan dengan langkah-langkah:
[tex]( {2}^{29} + {2}^{29} ) \div {1.024}^{2}[/tex]
[tex] = {2}^{29 + 1} \div ( {2}^{10} ) {}^{2} [/tex]
[tex] = {2}^{30} \div {2}^{20} [/tex]
[tex] = {2}^{30 - 20} [/tex]
[tex] = {2}^{10} [/tex]
[answer.2.content]
